What is the output of below program, why and what is the concept guiding
the output?
public class Test {
public static void main(String[] args) {
try {
String str = null;
doSomething(str);
System.out.println("1");
} catch (RuntimeException e) {
System.out.println("2");
}
}
public static void doSomething(String str) {
try {
System.out.println(str.length());
} finally {
return;
}
}
}
1 comment(s) to... “question 5”
1 comments:
Output is :
1
Though there exists a Null pointer exception in the doSomething method,
the finally block has ‘return’ in it signifying a normal termination of
the method. Hence, the code continues to print 1.
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